C语言中如何在构造体内定义函数

靓仔牛奶 · 发布于 2023-4-20 10:51:59

如何在构造体内定义函数

构造体中引入函数

#include <stdio.h>

struct student {
   char *name;
   int age;

   void (*printInfo)(struct student *stu);
};

void printInfo(struct student *stu)
{
   printf("name = %s, age = %d", stu->name, stu->age);
}

int main(int argc, char**argv)
{
   struct student students[] = {
       {"zhangsan", 10, printInfo},
       {"lisi", 26, printInfo},
   };

   students[0].printInfo(&students[0]);
   students[1].printInfo(&students[1]);
}
C++中构造体引入

#include <stdio.h>

struct student {
   char *name;
   int age;

   void printInfo(void)
   {
       printf("name = %s, age = %d\n", name, age);
   }
};

int main(int argc, char**argv)
{
   struct student students[] = {
       {"zhangsan", 10},
       {"lisi", 26},
   };

   students[0].printInfo();
   students[1].printInfo();
}
C++中类引入

#include <stdio.h>

class student {
public:
   char *name;
   int age;

   void printInfo(void)
   {
       printf("name = %s, age = %d\n", name, age);
   }
};

int main(int argc, char**argv)
{
   struct student students[] = {
       {"zhangsan", 10},
       {"lisi", 26},
   };

   students[0].printInfo();
   students[1].printInfo();
}
构造体成员有函数的定义与使用

```c

#include <stdio.h>
typedef int (*FunHandle)(int, int); //定义指向函数的指针
struct Example
{
int a;
int b;
FunHandle fun; //函数作为构造体成员
};

int add(int, int);

int main()
{
struct Example ex;
int r;
ex.a = 1;
ex.b = 2;
ex.fun = add;
r = ex.fun(ex.a, ex.b); //构造体中函数的使用
printf("%d + %d = %d \n", ex.a, ex.b, r);
return 0;
}

int add(int a, int b)
{
return a+b;
总结

以上为个人经历，希望能给大家一个参考，也希望大家多多支持网站。